I know the math says 1/3

>i know the math says 1/3
>i physically did this with actual coins though
>came out 1/2
>you can either believe the silly symbols we call numbers or physical observable reality
>try it yourself if you don't believe me

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>>i physically did this with actual coins though
>>came out 1/2

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>You didn't win the lottery the last 100 times you played. What are the odds you'll win it this time?

Math illiteracy is the reason that running a gambling enterprise is guaranteed money (unless you're trump.)

What's your sample size dumbass

my jaw is dropped. if you guys wanna believe lies then be my guest. otherwise give some coins a few flips and stop being so stubborn

Since you're a dumbfuck and dont understand statistics lemme sum it up for you. You got 3 possible situation that might happen cuz the text said at least one was heads up aka. 1 heads 1 tails/ 2 heads / 2 tails. So the probability would be 1/3 not 1/2(the probability of a coin landing on head or tails)

The real answer here is /thread.

Getting 1/3 is a fallacy anyways. To come to the conclusion that the odds are 1/3, you need to assume that the results are either TT, HT, TH, or HH. Obviously TT shouldn't be counted, meaning your odds are between HT, TH, and HH, hence 1/3 for two heads. BUT, that's a dumbass cuck way to look at it where you don't understand the actual question, because that's still considering the existence of a TT flip.

Because you're not including TT, the condition to check for a second heads is ALWAYS going to be that the first heads is fulfilled, leaving it up to that single second coin to be heads or not.

In other words, the math shouldnt be 'HT, TH, or HH, so it's 1/3'. It should be 'Coin 1 ALWAYS hits heads because that's the condition that needs to be met, and Coin 2 is either H or T, so its 1/2'

>try it yourself if you don't believe me
Challenge accepted. pic related

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In addition, whether or not the first coin is Heads or the second coin is Heads, that other coin still relies on 1/2 odds to get a second heads. You're either smooth brain and still think the odds are 1/3 or you recognize reality like OP.

your probability doesnt have shit on physical tests. you are the absolute state of dumbass

You either did it wrong or you didnt do it enough
he's wrong though

then something is wrong with your code because physically doing it in real life yields 1/2

all this post tells me is you didnt flip a single coin

Like i said already. You either did it wrong or didnt do it enough times. And im willing to bet the former. Let me guess. You left one coin on heads?
Im this guy so i flipped 2 coins 10,000 times

>Because you're not including TT, the condition to check for a second heads is ALWAYS going to be that the first heads is fulfilled, leaving it up to that single second coin to be heads or not.
No, you've fucked up.
The probability of two heads if the first flip gave heads is 50%. That's not what the question is asking.
The question is asking what the probability of two heads is in all cases where at least one flip gives heads (i.e. also including cases where the first flip gave tails).

You actually sum up the fallacy really well. The original post isn't asking what is the probably if there are 10,000 fair double coin flips. The post is asking the probability for ONE heads if the condition of there being another heads is met. Basically what said. Coin 1 is heads? Whether or not Coin 2 is also heads is 1/2. Coin 2 is heads? Whether or not coin 1 is heads is 1/2. It's 1/2 either way.

>Let me guess. You left one coin on heads
no i didnt do that and please physically try it if you dont believe me

My guy the math to get the true answer isnt rolls with two heasd divided by rolls with one heads. It's just rolls with heads after the original heads condition is met.

im content with the code. No bias, no human error. less time consuming, just numbers. It works fine with flipping one coin and the numbers split 50/50 so i dont see why we can't get a little bit more complicated

what the actual fuck is the point of considering such problems if you reject the physical results of it? wtfffff

>Coin 1 is heads
>Coin 2 is heads
So your almost there. You seem to recognize there's more than one way two get HT. now you just need to acknowledge the rest?
what's wrong with a simulation? Im telling you man, you did it wrong somehow

a simulation can never have more weight than the real thing wtf??

it works fine if we simulate other things that we know the answer too. so its not a problem with the code

Not the python guy, but you idiots "proving" it's 50% always do it wrong. You don't do the second flip when the first flip is tails, so you're not counting the "either flip gives heads" properly.

sir. if your code doesnt match reality and you still think its right idk what to tell you

it does. you just did the test wrong. i put my code for everyone to see and rip apart. post a vid of you doing the physical test then
they think the "first" coin has to be heads

>You don't do the second flip when the first flip is tails
where in this entire thread did i say i do the second flip when the first flip is tails?

well you freaking did something

>post a vid of you doing the physical test then
because anons wont accuse me of editing the footage. thats why im telling anons to try it themselves so they dont have to take my word for it

sir i am apparently the only user that applied reality to this problem

post anything, post the results like, "HT, HT, TH, HH etc", hell post your numbers, post anything other than "i did it and you're wrong"