How smart is Any Forums?

How smart is Any Forums?

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100% plus infinity

Stfu faggot

The chance is exactly zero: Euro coins don’t have a head.

/thread

Some of them do.

1/3

A coin is flipped and a douche bag was elected president. What are the odds of the coin being heads and a douche bag being elected as president?

Easy: 1/2

It doesn't matter if the ancillary condition was either a douche bag being elected or second coin being elected 'heads'. That ancillary outcome is stated as a given and is therefore unrelated to the odds of the remaining coin landing on heads.

The answer is 1/2.

it matters. theres 4 combinations on a normal flip of two coins. the condition eliminates one of them

>second coin being elected 'heads'.
second coin could be tails though, so you're wrong. There are 3 equally likely outcomes
heads - heads
heads - tails
tails - heads

1/3

Think of it this way. A coin is flipped and you buy a lottery ticket. The lottery ticket happens to be a winner. What are the chances that coin landed on heads?

1/2

1/2 per toss, two tosses, so 1/4

You don't understand what you are saying.

That's without the condition. Now try again.

Let us define our terms:
>Probability is the number of times a given outcome occurs divided by the number of all possible outcomes.

If two coins are tossed and have landed, there are four possible outcomes: HH, HT, TH, and TT. So if two coins are tossed, the probability that both landed heads is 1/4.

But the question is *what is the probability that both coins landed heads given that one coin has landed heads*. In this situation, the list of all possible outcomes is HH, HT, and TH. So the probability that both coins landed heads when at least one of them has landed heads is 1/3

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Write a Monte Carlo computer simulation. Generate to independent events, each have two outcomes, with a perfect 50% chance of 'yes' or 'no'. Ignore all trials where there is not at least one 'yes'. Now ignore whichever event was a 'yes'. It's possible both events were 'yes', and in that case it doesn't matter which one you chose. Throw it away and ignore it. You now have one remaining event, independent on the other event that you tossed aside, which is either a 'yes' or a 'no', with a 50% chance of either outcome. If you run the simulation you'll clearly see it yields the correct answer of 1/2.

no it doesnt. its been done multiple times. and it doesnt show 1/2

Alice tosses a coin in London. Bob tosses a coin in Paris. They call each other and confirm that at least one of them has 'heads'. If neither of them has heads then they both flip again, until one of them gets a head. If Alice has a head the she eliminates herself from the game completely. If Bob has the 'head' then he eliminates himself from the game. If they both have heads then the choose randomly who will be eliminated (it doesn't matter) That leaves one remaining player and one coin. When that coin was flipped the odds of it being a 'head' were 1/2.

Fix your code. If you're getting 1/3 then your code does not match the wording of the question.

it follows it exactly. plus your over complicating it. You just need to "flip" two "coins" and count the amount of times atleast one was heads and then get the percentage of HH within that

1/3

Attached: coinsFlipPython.png (736x433, 59.8K)

Bob heads, Alice heads
or
Bob Heads, Alice tails
or
Bob tails, Alice heads

1/3

Do experiment right now.
Put a coin down on heads because heads is already promised in the question. 50-50 for the other coin.