I can't solve this.
I don't think you can either
I can't solve this
Lucas Rogers
Zachary Stewart
Give me any 2 numbers and I'll solve it for you
Justin Harris
solution = lambda a,b: sum([a, b])
Jace Hill
=SUM(A1:A2)
Parker Campbell
Can't you just increment the first number for nth time where n is the second number and it's incremented by a bullshit division that adds up to one?
if you absolutely can't use a + in the loop you can just use a while.
Kevin Sullivan
Binary XOR is how your CPU makes addition... EE wins again
Anthony Cruz
unsigned int add(unsigned int a, unsigned int b)
{
unsigned int carry = a & b;
unsigned int result = a ^ b;
while(carry != 0)
{
unsigned int shiftedcarry = carry
Tyler Murphy
t. EE
Lincoln Russell
import integerSummer from 'integer-sum'
import React from 'react'
import bootstrap from 'bootstrap'
import wrapper from 'timmys-wrapper'
const App = () => {
const number = 1
const number = 2
if (number === 1 && number2 === 2)
{
const sum = integerSummer(1 + 2)
return (
{sum})
}}
Austin Kelly
>using +
>Calling functions that use +
Jaxson Thomas
a+b. If you want me to use a certain operator ask a question that I couldn't solve using the operators you don't want me to use. The question also has to have merit in the real world. Otherwise you can go fuck yourself and your mother.
Chase White
>Calling functions that use +
That's an implementation detail.
Nothing to do with the language itself and therefore solving the problem.
Ian Flores
>add ecx, edx
easy
Sebastian Morris
Do some bitshift shit I guess
Zachary Perry
from operator import add
solution = add(a, b)
Brayden Jenkins
2ez
sum(a,b,) = log(exp(a)*exp(b))
Sebastian Gray
in Perl this is just
++$a while ($b--);
Zachary Cox
>unsigned int
>-1000
Matthew Rodriguez
```
fn get_sum(mut a: u16, mut b: u16) -> u16 {
while b != 0 {
let c = a & b;
a = a ^ b;
b = c
Isaac Garcia
>negative numbers
Henry Howard
def sum(a, b):
lst = []
for i in range(a): lst.append(1)
for i in range(b): lst.append(1)
return len(lst)
Jeremiah Mitchell
big brain guy here
Brody Evans
Also, negative numbers
Camden Richardson
You can try it in your Javascript console.
It even works with floating point.
let sum = (a,b) => Math.log(Math.exp(a)*Math.exp(b));
sum(-1, 10); //9
sum(-10, -100); // -110
Austin Cook
>++
>---
so in Perl not use one of operators is use them all twice
Jace Howard
log(e^a e^b) = log e^a + log e^b = a + b
Caleb Hall
Honestly if this is what it takes to work at Google we need to stop calling them top tier engineer and just call them autists with a photographic memory because noone is going to know this due to years of coming across it in the real world.
Sebastian Lewis
god I fucking hate leetcode how is this supposed to be something that people are just supposed to know on the fly in a job interview unless you have a background in EE?
basically the answer is to use bitwise operators with a carry but honestly I would have no idea how to answer this on the fly without googling
Nicholas Hall
>do a+b without using "+" or "-"
Austin Morgan
def sum(a, b):
lst = []
for i in range(a): lst.append(1)
for i in range(b): lst.append(1)
for i in range(-1 * a): lst.pop()
for i in range(-1 * b): lst.pop()
return len(lst)
If I'm allowed to consider -1 a constant number instead of operator - applied to 1.
Wyatt Ramirez
>god I fucking hate leetcode how is this supposed to be something that people are just supposed to know on the fly in a job interview unless you have a background in EE?
I have a background in computer science and I knew this.
Carson Baker
>t. ESL