Let's see how smart Any Forums is

Let's see how smart Any Forums is

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Did you run out of gold and silver?

50%

2/3.

Assuming that the third box, with only red balls is out of the question, we have two possibilities. Either we picked the crate with two green balls or one green and one red ball.

We picked up one green ball, leaving us two possible scenarios, either our crate contains two green balls or it contained one green ball and now has a red ball in it.

Two options, two outcomes. Heads or tails, 50/50

Your both wrong, the answer is 2/3.

how? you picked a green ball meaning you couldn't have picked the third box. you either picked the only green in the second box, or from the first which is only green. 50/50 wtf

Why? The third crate containing only red balls is out of the question/equation

1/3 x 2/3 meaning = 3/6

There are 3 green balls you could have picked. If you picked the 1st or 2nd, there is another green ball in the box, if you picked the 3rd there is not, so 2 out 3 possible green balls result in another green ball.

Because this can actually represent one of 3 different scenarios, either:
A. You picked the first ball and the next ball will be the second ball which is green
B. You picked the second ball and the next ball will be the first ball which is green
C. You picked the third ball and the next ball will be the fourth ball which is red
2 of these three scenarios result in another green ball so the probability of it is 2/3. It's a pretty famous paradox called the Bertrand's Box Paradox and in a way also ties back to the Monty Hall Problem. There's like 3 Vsause2 videos on it, go give them a watch.

Without doing the maths, it comes down to if you picked box one you would always pull a green ball but if you picked box two you have a 50% chance to pull green ball. So if you pull a green ball chances are you pulled from a box with two green balls

...

Statistician here.

We can automatically rule out the red/red box since you pulled a green ball.

That means you can either pull:

Green
Green
Red

Meaning your odds of pulling another green ball is 2/3


>also I’m not a statistician

Actually, on second thought, it is 50/50 because the two boxes are separate. You can’t add the greens from different boxes.

Box 3 is out.

Box 2: if he pulled a green then 100% chance of red

Box 1: if he pulled green then 100% chance of green.

Therefore 50/50

The mistake you all are making is saying “there’s 2 greens and 1 red” but you can’t mix the boxes together since the participant can only have his hand in ONE box.

This. Thank you for the correction

fucker really watched Vsauce and thinks hes hot shit. best of all, he doesnt even spell Vsauce correctly.

This is literally just the difference between academic statics where the very specific wording and technicalities allow for a result of 1/3

While in practical terms the result is 50/50

Reaching into OP's mom's mouth the odds that the balls you pulled out would be mine is 100%

actually you have to mix them. since weve no idea which box youve picked. therefore all the possibilities have to be accounted for

I also learned about it in high school.