Is fermat last theorem the new fizzbuzz? come on, if you can't solve it you are not gonna make it

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a=0
b=0
c=0
0+0=0
QED

\forall n \in Z > 2
\forall a, b, c \in Z
a^n + b^n != c^n

n > 2, not a,b,c

Brainlet
inb4 all the computer """science""" majors start posting brainlet nonsense

>letters in math
Yeah this is unsolvable, i tested 5 for loops but since theyre all letters i didnt know what to do with them

n=infinity
a^infinity + b^infinity = c^infinity
infinity + infinity = infinity

>infinity
not a number

Retard kek

bump

Qed: Real numbers don't exist.

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the question says it cannot be solved. so why bother solving it then? i shall allocate my time to more valueable, more solveable matters.

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NaN

>if you can't solve it you are not gonna make it
You already posted this and it was determined that people who bother trying to solve it are the unemployed ones

YWNBAW

I found an interesting proof of this, but this post is not large enough to write it down

post it faggit

> Math.pow(844487, 5) + Math.pow(1288439, 5) === Math.pow(1318202, 5)
true
ez

Found a solution guys:
import math
print math.pow(18014398509481984,3) + math.pow(1, 3) == math.pow(18014398509481983,3)

This gives false for me? It's supposed to be JS, right?

WTF? how does this work??

>This gives false for me? It's supposed to be JS, right?
Huh, it works in node/Chromium/V8 but not in Firefox. Slightly different implementations of Math.pow?