Let's see how smart Any Forums is. If you can't figure out the answer to this question you're clearly not smart enough to invest. Here is the puzzle:
You are on an island with 12 different natives.
11 of the natives are the exact same weight.
1 of the natives weighs slightly less or more than the other natives (you are unsure which it is)
There is a seesaw on the island, but you can only use it a total of three times.
Figure out a way to with 100% certainty pinpoint which of the natives weighs differently than the others.
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If you can figure this out you're smarter than the average biz/tard and will make it. This is not just a game or puzzle, but it tests your ability to weigh your options, just like any good trader should be able to do. Find the path to success, and don't let me down Any Forums
You shouldn't be investing if you can't solve this puzzle
I don't believe you can do it with 100% certainty, unless you know that one native is heavier or lighter from the get go.
Otherwise you're left in a situation where you have to guess after the third weigh.
6 x 6 - left is heavier (but are they all the same weight or is one heavier? One on the other end could be lighter)
Say left is heavier you have to put half on each side - 3 x 3
Say they're even, now you don't have enough weighs to check the other previous 6.
Didnt read
Buy at X price
Sell at price that is higher than X
End of story
It is possible to do it with just three uses of the seesaw. I did it, and I can explain it later if no one gets it. I'll admit it was a damn hard puzzle though. I had to really think about it for a long while.
Easy.
6 on each side. Take the side that's heaviest. Then 3 on each side. Take the side that's heaviest. Then two on each side. If equal the unweighed one is heaviest. Otherwise its whichever one comes out heavier from being weighed against each other. Where's my prize?
You're incorrect.
You don't know if the one native that is an outlier weighs more or less than the other natives.
I'll be checking the thread later then, my assumption is that it's a trick question designed to make biztards chase their own tail
It's not, I swear. There is a very real answer. Just in case this thread dies I'll make a followup thread or something that explains it, but I'll keep a close eye on the thread so I can explain it if I need to or if it goes on for too long.
>get half of crew on either side
>deduce which half has the lighter person
>discard the rest of them
>now down to 6 natives
>do it again
>now down to 3 natives
>put 2 of them on the seesaw
>if they weigh the same, it's the guy not on the seesaw
>if they weight differently, its the guy who isn't on the low end of the seesaw
Half the natives on each side reduces the pool to 6. Half of that reduces to 3. Weigh 2 of those 3. If the seesaw is even, it’s the one you didn’t weigh. If one side is lighter the. It’s the lighter side.
retard
>
Incorrect. You don't know if that one native weighs heavier or lighter than the rest of them. Come on Any Forums you're better than this. Someone else should be able to get it.
Damn beat me to it. Yep this is the answer. Now see if Any Forums can solve the eye color problem
this would work if you knew whether the native was heavier or lighter. there is a chance when you do the first 3 - 3 weighing that the two sides weigh the same
All of you are still wrong. You're all working under the assumption you know the one outlier is weighed heavier or lighter, but you have no clue how much they weigh in comparison to the rest of the natives.
put 4 on one side, 4 on the other
if they're even, the lighter person is in the remaining 4
proceed weighing 2 vs 2 in the lighter group
then 1 v 1 the same way
easy nigger
You can split them into groups of four, this gives you a control to identify whether the outlier is heavier/lighter, and will help you pinpoint the outlier to a group of four. I’m tired and can’t be fucked thinking it all the way through but I think this is how you would start?
So far the smartest answer, but still incorrect. The native who weighs differently is either heavier or lighter so there is still a 33% chance you'd end up with the lighter group being level since the last native could be heavier. Props for trying something different.
1st use
3 on each side to start makes 6.
lets assume its neutral and it stays levels, the first 6 would be eliminated,
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2nd us, 3 more on each side, the final 6
let's assume that the left side sinks into the ground and the opposite side it now higher
that would be that someone is less or more in weight
go around the island fining similar sized rocks, go through the last 6 hand each a rock until it balances itself and you find the person with an odd weight,
3rd use
remove said person and bring a person from the first group, then walla, blance
>coof on unvaxinated natives
>not my fucking problem
>4 on each side
>if there is a difference, swap 2 from either side of the seesaw
>if there is no difference, swap two from one side with 2 of the remaining islanders
>at this point, you should have it narrowed down to two people
>either they were on the heavier/lighter side in both seesaw attempts, or they were on the heavier/lighter side after swapping the 2 new people out
>at this point, weight the 2 against eachother
You can just ask them their weight