>get useless degree >doesn't even teach you basic math >owe $200,000 on useless degree >expect taxpayers to bail you out
You took out a loan. You pay it back. >but it impoverishes an entire generation and gives the banks more power Not my problem. I paid my way through college back in the 80s, no reason you lazy millennials can't cut the avacado toast and Starbucks and do the same.
These probability troll threads are literally older than Any Forums. People think that it is hilarious to insist on an incorrect answer like 2/3 and then make people who don't know that it is a troll go insane trying to 'explain'
This is a well known and simple probability problem that anyone can google and have a simple explanation within 2 minutes. Anyone insisting it is 2/3 or 1/3 is definitely trolling.
Dominic Rogers
1/2 You've already established that you got one of the boxes with a gold ball in it so that means you either have the box with the 2 gold balls or you don't.
Ayden Sanchez
Actually if you go to /sci/ they push the 2/3 math constantly because they're retarded.
Mason Cruz
2/3rds. Google it. You repeat the test and it's 2/3rds because you have 2 chances of grabbing the dual gold ball box. And, 1 chance to grab the mixed ball box.
No. The host always removes a door so your odds are always going to be 1/2.
Camden Nelson
Same box, leaf. L2read.
Jaxon Hall
You already picked a gold ball, this means you don't have the first box which has 2 silver ones.
The odds that you picked the ball from the box with the 1 silver and 1 gold ball is 1/3, and the probability you picked the ball from the box with two gold balls is 2/3.
Its bertrands problem, google it.
I never took a loan for school, I make way over 100k. Life is good if you're not a complete retard.
But don't you understand it is the same as a business that was forced closed by government because of virus they funded, and using the business as a pass through entity to give out temporary unemployment is the same gender studies loans.
conditional probability faggot. You already picked a gold ball, so the probabilities related to boxes containing gold balls no longer relate. You absolutely have box 1 or 2. box 1 offers 100% chance of gold ball, box 2 offers 0% chance. Odds of next ball being gold is 50%.
I love these threads. All you dumb niggers rushing to show how fucking ignorant you are.
2/3
Angel Taylor
A troll version of a problem like this that I like is asking if you flip a coin 100 times and it comes up heads every time, what's the chance it'll be heads on the next flip?
The normal answer is 50% of course, but since the problem doesn't specify the coin is fair and the chance of flipping heads 100 times in a row is vanishingly small, I think saying the coin must have two heads and the chance is 100% is fine. It's a question if the word problem is just a container for a purely mathmatical expression or if you take all the information seriously.
Liam Cook
I dont honestly see the difference in your programming except for the difference in the 2nd index which I dont think matters since the first persons solution shuffles the array. Regardless I know your right since the math has already been proven on Wikipedia
Dylan Bell
This again. Look just do the experiment 100 times and log you results You will find the real answer. Clue : it's not 50/50 do some bigboi maths
2/3 b/c this is just simple bayesian stats. We want P(A | B) where A is us choosing the box with two gold balls and B is the first ball being gold. So by the equation P(A | B) = P(B | A)*P(A)/P(B)=1*(1/3)/(1/2)=2/3
Jonathan Lee
Once you have picked a gold ball, it is established that it can only be one of 2 boxes you are picking from
BUT...
but but but but but
You have to think about what are the odds you grabbed that gold ball from the box with 2 gold balls, or jut but only one gold ball (thus the next ball will be silver)
This is the clue that will help you answer the question Batman (Robert Pattinson not Ben Affleck)
EDIT: Thanks for the gold kind stranger
EDIT 2: Woe I didn't expect this to blow up the way it did. RIP my inbox
Final edit - please keep the racism to a minimum guys
Juan Evans
I'll spoil the beans. If you append print(len(boxes[0][0])) print(len(boxes[0][1])) print(len(boxes[1][0])) print(len(boxes[1][1])) print(len(boxes[2][0])) print(len(boxes[2][1])) you can see there's not just 'g' or 's', but also an invisible character if you use ord() on this char to get its value, it'll show to be unicode 847, or en.wikipedia.org/wiki/Combining_grapheme_joiner one thing that's a bit random and changes per run is what letter it gets appended to: boxes = ['g', 'g'] will either turn out to be ['g'+joiner, 'g'] or ['g', joiner+'g']. But that won't matter in the end for the calculation, which is tailored to be 1/2. You can tack on any amount of joiners to get whatever value you want.