>this filters the retarded American
This filters the retarded American
Amerimutt cope is delicious
NEIN
The answer is 1
It's 9.
9
pi
6/6 = 1
1+ 2 = 3
3 x 2 = 6
6/6 = 1
Explain how this is incorrect
Would you distribute the 2? That's the question. Also only a faggot would leave ambiguity like that.
2+1=3
2x3=6
6\6=1
>incorrectly written equation
No user, you are the retards
9
because u should 6/2 and then *3
Old way is 1, common core is 9.
The question is written incorrectly, it should be either 6÷(2(1+2))= or (6÷2)(1+2)=
=1
1
Please stop making these easy math threads. At least post something post high school.
So we go by BODMAS
6÷2(1+2)
6÷2+4
3+4
7
9
That is implied multiplication by juxtaposition. Even calculators differ in the order they evaluate this. For example, the TI-82 is reported to prioritize juxtaposition and the TI-83 does not.
Nowadays, juxtaposition is usually expected to bind more strongly than explicit multiplication. I would evaluate it to 1. It's convention, not unlike operator precedence in programming languages.
>Distributive rule
>6/2(1+2)
>3(1+2)
>3+6
=9
If you're a top it's 6 and 9 for bottoms
This is racist.
The gay prove their stupidity once more
2() comes first.
Jewish hands wrote this,
Math is a trick created by a long-nose tribe.
If you solve it like this:
6/2=3
1+2=3
3x3=9
you’re actually mentally ill
>Mutts mutts mutts
>Europoors europoors europoors
>More D&C
>The only smart reply in this thread
Stop bumping slide threads
Why u need 3+6
It’s correct
P Parentheses
E Exponent
M Multiplication
D Division
A Addition
S Subtraction
/Thread
This.
>=6/2(1+2)
>=6/2(3)
>=6/6
>=canadians are gay leaf faggots now kys you north mexico scum
>This pemdas vs. pedmas slide thread again
Pic related is why real ones use RPN and decide for themselves instead of having a cuckbox pick convention.
Distribute 3(1+2) means you're taking the external times the quantity of the internal. You have to take care of everything outside the parentheses first before doing so or else you'll end up with 7.
You should be able to substitute x for any random variable and be able to solve it for its same variable if you do it right.