What the fuck is the logic here

what the fuck is the logic here

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and wtf is this one

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You're wasting your time taking an IQ test. Accept that you are retarded and move on.

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Out yourself as a brainlet. The answer is clear--almost trivial but you are bumbling and stumbling on it like some low IQ monkey. How embarrassing for you.

Is it 2?

5

subtracting a block form the top bits each iteration on first row and 2 from the bottom ones
subtracting 1 from the top and 2 from bottoms from each on second row
bottom row subtracting 1 from top 1 from bottom left and 2 from bottom right

A. The X-axis (sticking out towards the right) one loses two blocks.
B. The Y axis (left) loses one block each time.
C. The Z axis (up) loses one each time.

From A), we know that it's 1, 2, 4, 5, 7, or 8.
From B), we know that 1, 2, 5, or 7.
From C, we know that it's 1, 2, or 5.

However, the X axis is four blocks long - so it can't be 5 (only 3 blocks). Therefore, it's 1 or 2.
And the Y axis is two blocks long - so it can't be 1 (only one block out).

It's 2.

8, maybe. I dunno.

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It isn't clear if the pattern is supposed to be in the vertical columns or the horizontal rows. If it is vertical then the pattern I see is that each example in each column has the same number of blocks regardless of the arrangement, therefore the answer is number 2.

none of the above

What he said.

Why

1
Each 3d arrangement appears on the grid 3 times but rotated, number one below is the same as top right and center in the grid but rotated the same way as the other examples.

2. The number of blocks in each column is the same.
1. There are three different arrangements of blocks facing in three different directions.

figure 1 is the correct one.
movement only occurs int he top three cubes, logiclly the following shape is 1

Number 2

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2 works horizontally as well

left row
top extra bits = 4
left extra bits = 3
right extra bits = 4

middle row
top extra bits = 3
left extra bits = 2
right extra bits = 2

right row
top extra bits = 2
left extra bits = 1
right extra bits = 0

answer 2 is the only one that fulfills the same number of extra bits on all three arms for the right row

They should have asked what would be in tile 4,4 instead of 3,3. That would at least require a two-step pattern

Rolling, hope I get to fuck number 3

5 chads rise up

2

Damn I'm a dumb fuck... but still smarter than the vaxxed masses, who in turn are smarter than niggers.
Superiority restored.

5
Dunno why people say it’s 1, it’s missing a block compared to the other two

oh wait nvm :(

man,it's really interesting to see where our thoughts differ
(or at least our articulations thereof)
you counted the terminal block of each arm as being in the variable part of the configuration whereas i did not

all vaxtards will burn in hell for taking the mark

Fucks sake I didn’t mean 5 I meant 2

Loses 4 blocks every time from l to r.

The only answer with 13 blocks is #2

The beauty of math is that it is simply true, so our different routes and thought processes still detected the real pattern

5. There are 3 endpoints which can change or stay static, there’s a sequence that could be valid for other moves but the end choices limit the what-ifs

If you can't do these you aren't white

Answer is probably 5
>t. 115 iq

Cry about it chud soon we will gaslight you all and pretend the mandates never even existed