Can you solve this?

can you solve this?

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math.ucr.edu/~res/math133-2020/week4/sections_3.1-3.2/hard-easy-geometry-problem.pdf
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>twin tails
>black
>glasses
is there a worst combo in existance?

She's not black, she's American.

You best shut your whore mouth

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she's just dark skinned, her features are german, like illya

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21

>she's just dark skinned
yeah user, that was being black means

can i make notes or do i have to do it in my head? i could probably solve it on paper but my brain capacity fell off a cliff after i was done with school

looks like around 60-70, don't care. It's time for some correction on that teacher

you guys are being tricked. this is not solvable because there are 4 angles in there that make up all solutions. alpha can literally be anything from 0 to 130 exclusive

>a triangle with 60º and 70º giving any result higher that 90º
no need to see the rest to know its bulshit

first thing I noticed too, also makes the supplementary angle 130º even though it is clearly acute

genetically they are the same except for the skin. the typical black has a wide nose half the face.

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i can't figure out the CDE triangle, don't know if it's because i'm just dumb or because you can't solve it without trigonometry
it's not to scale obviously

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alpha is 20

are you retarded?

Alpha is 70. The giant triangle is an isosceles triangle

let's see your solution smartass

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>i could probably solve it on paper
no, you couldn't math.ucr.edu/~res/math133-2020/week4/sections_3.1-3.2/hard-easy-geometry-problem.pdf

none of you could. these threads are always like this, with this image or some other one. someone gives you an olympiad-tier problem that looks innocent but you can't notice or refuse to notice, and people make fools of themselves without even knowing and nobody learns anything in the end

60°

>black

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Blacks have different facial structure too.

you can use the property of a quadrilateral to find the angles in CDE :

you know that EAC is 10° so you'll get a 10° difference between EDC and DEA.

that removes a degree of liberty from the equation and you can now solve for the angles, you 'll find α=20°