x - 7 == 19 + x
Make this expression evaluate to a truthy value using any programming language of your choice.
x - 7 == 19 + x
Make this expression evaluate to a truthy value using any programming language of your choice.
Change == to !=
Next
You must not alter the expression in any way
Do your own homework.
using namespace std;
int main(){
double x = 1.0/0.0;
if(x - 7 == 19 + x){
cout
if ("x - 7 == 19 + x")
{
printf("OP is a faggot\n");
}
This isnt even possible you retard
class X: __sub__ = __radd__ = lambda *_: True
x = X()
assert x - 7 == 19 + x
brainlet detected
what's a "Truthy" value?
check (your IQ) and mate (have sex) OP
Just overload addition and subtraction on all types to return 0 or some other constant.
modulo 26
We define the limit operator in the extension of the real numbers R+, which is the closed set [-inf, inf].
In that case
lim (x - 7) = lim (19 + x) = -inf or inf
var x = 2.0 ** 58
x - 7 == 19 + x
x - 7 = x + 19 (mod 26)
0 = 26 (mod 26)
checks out
this will never be true tho so jokes on you
>she doesn't know
In J this is just
x =: 1
x - 7 == 19 + x
1
A truthy value is a value that will be interpreted as true. For example, in python an empty list [] will be interpreted as false when you use it in an if statement, and a list with at least 1 item will be considered true [1]
"x - 7 == 19 + x" != NULL
retard
Int operator+(int i, const int& j)
{
Return 1;
}
Int operator-(int i, const int& j)
{
Return 1;
}
If (x - 7 == 19 + x)
{
Cout
x=1
if not(x - 7 == 19 + x):
print('OP is a faggot')
kek, good answer
x = 14
let me guess
js developer
big brain INF == INF
10/10 bait
I worked with people like you...
x = "ok"
new Date(x - 7 == 19 + x)
#define x 0||1
#include
bool nigger()
{
int x = - 25;
return (bool) x - 7 == 19 + x;
}
int main()
{
cout